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# Thermal Expansion Calculator

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The thermal expansion calculator helps to determine the linear expansion of a material according to the temperature change. If the temperature is more the material begins to expand. The thermal expansion formula is given as,
L = $\alpha \times L_{1}(T_{2}-T_{1})$
Where,
L
= linear expansion in length,
$\alpha$  = linear expansion coefficient,
$L_{1}$ = initial length of the material,
$T_{1}$ = initial temperature,
$T_{2}$ = final temperature.

## Steps

Step 1 : Put down the parameter values given in the problem.

Step 2 : Plug these variables in the formula and find out the unknown quantity

L = $\alpha \times L_{1}(T_{2}-T_{1})$

## Problems

Some solved problems related to Thermal expansion are given in this section.

### Solved Examples

Question 1: The initial length of a material is 15m, the temperature of this material is changed from 60°C to 85°C. Calculate the linear expansion in length, if the expansion coefficient is 1.2$\times10^{-6}°C^{-1}$.
Solution:

Given quantities are,
$L_{1}$ = 15m,
$\alpha$ = 1.2$\times10^{-6}$°C$^{-1}$,
$T_{1}$ = 60°C,
$T_{2}$ = 85°C.

Linear expansion of the given material is,
L = $\alpha \times L_{1}(T_{2}-T_{1})$
L = 1.2$\times10^{-6} \times$ 15(85-60) = 0.00045m

Question 2: The initial length of a material is given as 0.3m, the temperature of this material is changed from 25°C to 95°C. Calculate the linear expansion in length if the expansion coefficient is 2.5$\times10^{-6}°C^{-1}$.

Solution:

Given quantities are,
$L_{1}$ = 0.3m,
$\alpha$ = 2.5$\times10^{-6}$°C$^{-1}$,
$T_{1}$ = 25°C,
$T_{2}$ = 95°C.

Linear expansion of the given material is,
L = $\alpha \times L_{1}(T_{2}-T_{1})$
L = 2.5$\times10^{-6} \times$ 0.3(95-25) = 0.0000525m