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# LC Resonance Calculator

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This online calculator is used to determine the resonance frequency of an LC circuit. In this circuit we are using  an inductor and capacitor for producing current. So the resonance frequency is in terms of inductance and capacitance value. The formula for resonance frequency is,
$f_{0}$ = $\frac{1}{2\pi \sqrt{LC}}$
Where,
$f_{0}$ = resonance frequency,
L = inductance value,
C = capacitance value.

## Steps

Step 1 : Note down the given measures from the problem.

Step 2 : Plug in these values into the formula and find out the required value.

$f_{0}$ = $\frac{1}{2\pi \sqrt{LC}}$

## Problems

Some of the solved problems related to LC Resonance are given below.

### Solved Examples

Question 1: An electrical circuit consists of an inductor of inductance 2 mH and a capacitor of capacitance 5 $\mu$F. Calculate its resonance frequency?

Solution:

Given parameters are,
L = 2 mH = 2$\times10^{-3}$ H, C = 5 $\mu$F = 5$\times10^{-6}$ F
Formula for resonance frequency is,

$f_{0}$ = $\frac{1}{2\pi \sqrt{LC}}$

$f_{0}$ = $\frac{1}{2\times3.14 \sqrt{2\times10^{-3}\times5\times10^{-6}}}$

$f_{0}$ = $\frac{1}{0.000628}$ = 1592.35 Hz

Question 2: The inductance and capacitance value of an electrical circuit is given by 15 mH and 30 mF respectively. Find out the resonance frequency?

Solution:

Given parameters are,
L = 15 mH = 15$\times10^{-3}$ H, C = 30 mF = 30$\times10^{-3}$ F
Formula for resonance frequency is,

$f_{0}$ = $\frac{1}{2\pi \sqrt{LC}}$

$f_{0}$ = $\frac{1}{2\times3.14 \sqrt{15\times10^{-3}\times30\times10^{-3}}}$

$f_{0}$ = $\frac{1}{0.1332}$ = 7.506Hz