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# Equivalent Weight Calculator

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The equivalent weight calculator helps to determine the equivalent weight of acid and also base. The equivalent weight of acid is the amount of acid required to generate a hydrogen ion in a solution. To determine the equivalent weight of the acid, plug in all the required values into the equivalent weight first calculator given below. The equivalent weight of the base is the amount required to generate a hydroxide ion in a solution. Plug in all the values required to calculate the equivalent weight of the base into the second equivalent weight calculator.

The formulas to find the equivalent weight of the acid and base is given as,
Equivalent weight of acid = $\frac{Molecular \ weight \ of \ acid}{Basicity \ of \ acid}$

Equivalent weight of base = $\frac{Molecular \ weight \ of \ base}{Basicity \ of \ base}$

## Steps

Steps to determine the equivalent weight of acid and base :

Step 1 : Check whether the compound is acid or base and then find the molecular weight of the given compound.

Step 2 : Plug in all the values into the respective formula given and find the result accordingly.

Equivalent weight of acid = $\frac{Molecular \ weight \ of \ acid}{Basicity \ of \ acid}$

Equivalent weight of base = $\frac{Molecular \ weight \ of \ base}{Basicity \ of \ base}$

## Problems

Some of the problems are given below based on equivalent weight of acid and base.

### Solved Examples

Question 1: Calculate the equivalent weight of $H_{2}SO_{4}$.
Solution:
Given compound $H_{2}SO_{4}$ is an acid.

Molecular weight of $H_{2}SO_{4}$ = 2 $\times$ 1 + 32 + 4 $\times$ 16 = 98 g/mol

Basicity of $H_{2}SO_{4}$ = 2

Equivalent weight of $H_{2}SO_{4}$ = $\frac{Molecular \ weight \ of \ H_{2}SO_{4}}{Basicity \ of \ H_{2}SO_{4}}$

Equivalent weight of $H_{2}SO_{4}$ = $\frac{98}{2}$

Equivalent weight of $H_{2}SO_{4}$ = 49

Question 2: Calculate the equivalent weight of $Ca(OH)_2$.
Solution:
Given compound $Ca(OH)_2$ is a base.

Molecular weight of $Ca(OH)_2$ = 40 + 2 $\times$ 16 + 2 $\times$ 1  = 74 g/mol

Basicity of $Ca(OH)_2$ = 2

Equivalent weight of $Ca(OH)_2$ = $\frac{Molecular \ weight \ of \ Ca(OH)_2}{Basicity \ of \ Ca(OH)_2}$

Equivalent weight of $Ca(OH)_2$ = $\frac{74}{2}$

Equivalent weight of $Ca(OH)_2$ = 37 g