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# De Broglie Wavelength Calculator

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This online calculator helps to determine the de Broglie wavelength of a particle. If both wave and matter properties of a particle exist, it should have a certain wavelength called de Broglie wavelength. Which is given as,
$\lambda$ = $\frac{h}{p}$
Where,
h = Planck's constant,
p = magnitude of the particle's momentum.

This equation is known as de Broglie equation and \lambda is known as de Broglie wavelength of a particle.

## Steps

Step 1 : Note down the given parameters from the problem.

Step 2 : By using the formula, find out the unknown value

$\lambda$ = $\frac{h}{p}$.

## Problems

Let us discuss the problems related to de Broglie Wavelength.

### Solved Examples

Question 1: Find the de Broglie wavelength of an electron (m = 9.11$\times10^{-31}$ kg) moving at 7.30$\times10^{5}$ m/s.

Solution:

Given that,
m = 9.11$\times10^{-31}$ kg),
v =  7.30$\times10^{5}$ m/s,
h = 6.626$\times10^{-34}$ Js.

de Broglie wavelength of the given electron is,

$\lambda$ = $\frac{h}{p}$

We know that p = mv

So, $\lambda$ = $\frac{h}{mv}$

$\lambda$ = $\frac{6.626\times10^{-34}}{9.11\times10^{-31}\times7.30\times10^{5}}$ = 0.996$\times10^{-9}$ m = 0.996 nm

Question 2: Calculate the de Broglie wavelength of an electron whose momentum is 0.374$\times10^{-23}$ kgm/s and the Planck's constant is given as 6.626$\times10^{-34}$ Js.

Solution:

Given that,
p = 0.374$\times10^{-23}$ kgm/s,
h = 6.626$\times10^{-34}$ Js

de Broglie wavelength of the given electron is,

$\lambda$ = $\frac{h}{p}$

$\lambda$ = $\frac{6.626\times10^{-34}}{0.374\times10^{-23}}$ = 1.7$\times10^{-10}$ m = 1.7 Å