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Chemical Equation Calculator

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Chemical equation is a theoretical representation of a chemical reaction. As per the law of conservation of mass, same number of atoms should be present in every element of each side of the equation. Therefore, number of atoms present in reaction should balance the number of atoms in the product. Plug in the chemical equation into the chemical equation calculator to get the balanced chemical equation.
 

Steps

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Step 1 : Make a note of the given chemical equation and observe the number of atoms present in every element of the reaction.

Step 2 : Make a note of number of atoms on each side of the equation.

Step 3 : Balance each element of reactants one by one and finally make a balanced chemical equation.

Problems

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Given below are some of the solved problems based on balancing chemical equation.

Solved Examples

Question 1: Balance the chemical equation :
C$_{3}$H$_{8}$ + O$_{2}$ $\rightarrow $ H$_{2}$O + CO$_{2}$
Solution:
 
Given chemical reaction :
C$_{3}$H$_{8}$ + O$_{2}$ $\rightarrow $ H$_{2}$O + CO$_{2}$

Elements
Left
Right
C 3 1
H 8 2
O 2 3

To balance C, add 3 as coefficient of C on right side.

Elements
Left
Right
C 3 3
H 8 2
O 2 3

C$_{3}$H$_{8}$ + O$_{2}$ $\rightarrow $ H$_{2}$O + 3CO$_{2}$

Then, we need to balance H, so we need to add 4 as coefficient of H on right side.

Elements
Left
Right
C 3 3
H 8 8
O 2 10

C$_{3}$H$_{8}$ + O$_{2}$ $\rightarrow $ 4H$_{2}$O + 3CO$_{2}$

Now, finally we use to balance O. As we see that the number of O has become 10, we need to add 5 as coefficient in front of O in left side of the equation.

Elements
Left
Right
C 3 3
H 8 8
O 10
10

C$_{3}$H$_{8}$ + 5O$_{2}$ $\rightarrow $ 4H$_{2}$O + 3CO$_{2}$

 

Question 2: Balance the chemical equation :
Na + O$_{2}$ $\rightarrow $ Na$_{2}$O
Solution:
 
Given chemical reaction :
Na + O$_{2}$ $\rightarrow $ Na$_{2}$O

Elements
Left
Right
Na
1
2
O
2
1

To balance Na, add 2 as coefficient of Na on left side.

Elements
Left
Right
Na 2
2
O
2
1

2Na + O$_{2}$ $\rightarrow $ Na$_{2}$O

Then, we need to balance O, so we need to add 2 as coefficient of O on right side.

Elements
Left
Right
Na
2
4
O
2
2

2Na + O$_{2}$ $\rightarrow $ 2Na$_{2}$O

We need to balance Na again as there is only 2 number of atoms on right side. Therefore, we need to add 2 as coefficient of Na on left side.

Elements
Left
Right
Na
4
4
O
2
2

4Na + O$_{2}$ $\rightarrow $ 2Na$_{2}$O